英语词汇set intersection怎么读，是什么意思，单词翻译、读音、固定搭配用法和短语词组及例句-英汉双解词典

网络释义

1
?集合交
... 边角联合交会 linear-angular intersection 集合交 set intersection 汇合交通 merging traffic ...

短语

1
off set type intersection
错开式交叉路口

双语例句

1
For example in the filter expression $x[count(.|$y)=count($y)] (which is the only convenient way in XSLT 1.0 of doing a set intersection operation), Saxon will evaluate count($y) only once.
例如，在过滤器表达式 $x[count(.|$y)=count($y)] 中（它是 XSLT 1.0 中执行一组逻辑乘操作的唯一简便方法）中，Saxon 只对 count($y) 求值一次。
2
The permissions sets of the caller class and its ancestors (that is, all stack frames above this one) are not included in computing the intersection set.
调用类和它的上级（即所有在它上面的堆栈帧）的权限集都不包括在交集计算中。
3
The resulting set will be the intersection of the resulting sets of each spec.
结果集是每种规范的结果集的交集。

单词	set intersection
释义	set intersection 简明释义集合交网络释义 1 ?集合交 ... 边角联合交会 linear-angular intersection 集合交 set intersection 汇合交通 merging traffic ... 短语 1 off set type intersection 错开式交叉路口双语例句 1 For example in the filter expression $x[count(.\|$y)=count($y)] (which is the only convenient way in XSLT 1.0 of doing a set intersection operation), Saxon will evaluate count($y) only once. 例如，在过滤器表达式 $x[count(.\|$y)=count($y)] 中（它是 XSLT 1.0 中执行一组逻辑乘操作的唯一简便方法）中，Saxon 只对 count($y) 求值一次。 2 The permissions sets of the caller class and its ancestors (that is, all stack frames above this one) are not included in computing the intersection set. 调用类和它的上级（即所有在它上面的堆栈帧）的权限集都不包括在交集计算中。 3 The resulting set will be the intersection of the resulting sets of each spec. 结果集是每种规范的结果集的交集。
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