Suppose I set the angle of the ladder exactly at the critical point.
假设我使,梯子正好,处于这个临界角。
2
And the second point is of radius 3 and angle 1, which is up about there.
半径为2然后角度为1的一个点,也就是差不多在这儿，我认为为了确保我做的是。
3
self y Notice what I also do here, I create self dot y, give it a value, and then, oh cool, I can also set up what's the radius and angle for this point, by just doing a little bit of work.